In question 3. the rate of disappearance of O 2 was monitored. For the same bala

Question

In question 3. the rate of disappearance of O2 was monitored. For the same balanced reaction

O2 (aq) + 2 L-dopaH2 (aq) 2 H2O + 2 L-dopaox

and the data from the first row from the table above, what are the expected rates of appearance or disappearance of each chemical?

a. O2 _______________________ b. L-dopa-H2 _________________ c. H2O ______________________ d. L-dopaox ___________________

[O2] (mM) [L-dopaH2] (mM} rate loss of O2 (mMS-1) 4.2 1.7 1.2x!0-3 6.3 1.7 1.8x10-3 4.2 3.4 2.4x10-3 6.3 3.4 3.6x10-3

Explanation / Answer

The reaction is,

O2 (aq) + 2 L-dopaH2 (aq) 2 H2O + 2 L-dopaox

From the stoichiometric coefficients of the reactants and products, we can state the following relation between the rates of appearance or disappearance of each chemical

- d [O2] / dt = (1/2) x -d [L-dopaH2 ] / dt = (1/2) x d [H2O] / dt = (1/2) x d [L-dopaox ] / dt

Therefore,

Rate of dissapearance of O2 = - d [O2] / dt = 1.2 x 10^-3 mMS-1

Rate of dissapearance of L-dopaH2 = -d [L-dopaH2 ] / dt = 2 x 1.2 x 10^-3 = 2.4 x 10^-3 mMS-1

Rate of appearance of H2O = d [H2O] / dt = 2 x 1.2 x 10^-3 = 2.4 x 10^-3 mMS-1

Rate of appearance of L-dopaox = d [L-dopaox ] / dt = 2 x 1.2 x 10^-3 = 2.4 x 10^-3 mMS-1

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