Aspirin, C9H8O4, slowly decomposes at room temperature by reacting with water in

Question

Aspirin, C9H8O4, slowly decomposes at room temperature by reacting with water in the atmosphere too produce acetic acid, HC2H3O2, and 2-hydroxybenzoic acid, C7H6O3 (this is why old bottles of aspirin often smell like vinegar)

C9H8O4 + H2O = HC2H3O2 + C7H6O3 . Concentration and rate law are given.

[C9H8O4] (M)        [H2O] (M)           Rate (M/s)

0.0100                    0.0200               2.4 x 10-13

0.0100                     0.0800              9.6 x 10-13

0.0200                     0.0200              4.8 x 10-13

1) find the rate law for this reaction and 2) calculate k (give the correct units )

Explanation / Answer

from dat 1 , 3 :

order with respect ot C9H8O4 = 1

from dat 1 , 2 :

order with respect ot H2O = 1

1) rate law = k [C9H8O4]^1 [H2O]^ 1

order =1 + 1 = 2

2) from data 1

2.4 x 10-13 = k (0.0100) (0.0200)

k = 1.2 x 10^-9 M-1 s-1

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.