Pressure of 1.00 bar. When the stopcock is opened, the gas diffuses slowly throu

Question

Pressure of 1.00 bar. When the stopcock is opened, the gas diffuses slowly through the porous plug, and the piston moves slowly to the right. The process ends when the pressures are equalized and the piston stops moving. The system is the gas. Assume that during the process the temperature throughout the system differs only infinitesimally from 300.0 K and the pressure on both sides of the piston differs only infinitesimally from 1.00bar. Which of these terms correctly describes the process: isothermal, isobaric, isochoric reversible, irreversible? Calculate q and w

Explanation / Answer

An isochoric process, also called a constant-volume process, an isovolumetric process, or an isometric process, is a thermodynamic process during which the volume of the closed system undergoing such a process remains constant. V = 0

An isothermal process is a change of a system, in which the temperature remains constant: T = 0.

in above process presurre drops from from 3 bar to 1 bar, hence it is not isobaric process. hence irreversible.

Fianlly this is irreversible, isothermal and isochoric process.

Thank you, all the best.

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