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Question 2 of 12 General Chemistry University Science Books 4th Edition presente

ID: 940559 • Letter: Q

Question

Question 2 of 12 General Chemistry University Science Books 4th Edition presented by Sapling Learning Donald McQuarrie. Peter A. Rock Ethan Gallogly The decomposition of N205 can be described by the equation (soln) 4NO2 (soln) 0,(g) 2N,os Given these data for the reaction at 45°C in carbon tetrachloride solution calculate the average rate of reaction for each successive time interval Interval: 0 s to 145 s 145 s to 546 s Number Number Reaction rate: t (s) [N205 (M) 2.01 145 1.83 546 1.43 825 1.20 546 s to 825 s Number Map

Explanation / Answer

Solution :-

Formula to calculate the rate is as follows

Rate = -delta [N2O5]/delta T

Lets calculate the rate for the each step

1) Rate at 0 to 145 s

Rate = - [1.83-2.01]/145 s

        = 0.001241 M/s

2) Rate at 145 to 546 s

Rate = -[1.43 – 1.83]/(546-145)

         = 0.000998 M/s

3) Rate at 546 to 825 s

Rate = -[1.20 -1.43]/(825-546 s)

        = 0.000824 M/s

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