When the concentration of A is doubled, the rate for the reaction: 2A + B 2C qua

Question

When the concentration of A is doubled, the rate for the reaction: 2A + B 2C quadruples. When the concentration of B is doubled the rate remains the same. Which mechanism below is consistent with the experimental observations?

a. Step 1: A + B D (fast equilibrium)

Step 2: A + D 2 C (slow)

b. Step 1: A + B D (slow)

Step 2: A + D 2 C (fast equilibrium)

c. Step 1: 2 A D (slow)

Step 2: B + D E (fast)

Step 3: E 2 C (fast)

d. Step 1: 2 A D (fast equilibrium)

Step 2: B + D E (slow)

Step 3: E 2 C (fast)

Explanation / Answer

c. Step 1: 2 A D (slow)

Step 2: B + D E (fast)

Step 3: E 2 C (fast)

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.