PLEASE!!!!!! Show ALLLLLLLLL stoich /ICE setups and calculations!!!!!!!!! units
ID: 941787 • Letter: P
Question
PLEASE!!!!!! Show ALLLLLLLLL stoich/ICE setups and calculations!!!!!!!!! units and correct sig figs included
PLEASE!!!!!! Show ALLLLLLLLL stoich/ICE setups and calculations!!!!!!!!! units and correct sig figs included
PLEASE!!!!!! Show ALLLLLLLLL stoich/ICE setups and calculations!!!!!!!!! units and correct sig figs included
if you don't know what an ICE setup is here is a link describing: http://www.chem.purdue.edu/gchelp/howtosolveit/Equilibrium/ICEchart.htm
1. A 10.00 mL sample of 0.300 M benzoic acid (Ka=6.3*10^-5) is titrated with 0.100 M NaOH. Calculate the pH when:
a) 18.32 mL of base is added. pH=______
b) the equivalence point is reached. pH=______
c) 32.18 mL of base is added. pH=______
Explanation / Answer
1. No of mol of C6h5cooh = 10/1000*0.3 = 0.003 mol
pka = -log(6.3*10^(-5)) = 4.2
a)
No of mol of Base added = 18.32/1000*0.1 = 0.001832 mol
pH = pka + log(salt/base)
= 4.2 + log(0.001832 / (0.003-0.001832))
= 4.4
b) equivalence point is reached.
No of mol of acid = base
0.003 mol base is required
volume of base = 0.003/0.1 = 0.03 L = 30 ml
concentration of salt = 0.003 / (30+10) *1000 = 0.075 M
pH = 7+1/2(pka+logC)
= 7+1/2(4.2+log0.075)
= 8.54
c)
excess base = 32.18/1000*0.1 = 0.003218 - 0.003 = 0.000218 mol
concentration = 0.000218/(32.18+10) = 5.16*10^(-3)
pOH = -log(5.16*10^(-3))
= 2.28
pH = 14-2.28 = 11.72
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