What is the rate law for the following mechanism? CH 3 COOC 2 H 5 + H 2 O CH 3 C

Question

What is the rate law for the following mechanism?

                        CH3COOC2H5 + H2O CH3COOC2H6+ + OH-                  (Slow)

                        CH3COOC2H6+           CH3COOH + C2H5+                     (Fast)

                        C2H5+   +      OH-         C2H5OH                                   (Fast)

A) Rate = k[CH3COOC2H5][H2O]2

B) Rate = k[C2H5OH]

C) Rate = k[CH3COOH]

D) Rate = k[CH3COOC2H5]

E) Rate = k[CH3COOC2H5][H2O]

The answer is E, but could you please give a detailed response on how to get to this answer? Thank you.

Explanation / Answer

rate equation can be written to the slowest step

that why we used to call rate determining step

in the above mechanism slow step is

CH3COOC2H5 + H2O CH3COOC2H6+ + OH-                  (Slow)

so rate will be

E) Rate = k[CH3COOC2H5][H2O]

but if you talk strictly we will not even consider the concentration H2O because compare to ethyl acetate water concentration is too high so this reaction we used to call as psudo unimolecular reaction

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