e previous | 2 of8 | next Part A r 0.500 mol of a nonvolatile nonelactrolyte are
ID: 942616 • Letter: E
Question
e previous | 2 of8 | next Part A r 0.500 mol of a nonvolatile nonelactrolyte are dissolved in 3 20 mol of water, what is the vapor pressure Piu,o of the resulting solution? The vapor pressure of pure water is 23.8 torr at 25 °C Express your answer numerically in torr Po 206 torr Hints My Answers Give Up Review Part Correct For solutions that contain solutes that dissociale, the number of moles of particdles produced must be taken into consideration in must be taken into consideration in determining the mole fraction of the solvent. For solutions that contain solutes that are volatile, the vapor pressure of the solution will be determined by both the solvent and the solutes. Solutions containing volatie solutes In of the partial pressures of the components: in sokutions composed of hwo Equids (A and B) each liquid contributes to the total vapor pressure above the solution. The total vapor pressure is the sum where P and are the vapor pressures of pure A and B, respectively Part B A solfon is composed of 1 70 mol cyd hexane (P Pua above this solution? Express your answer numerically in torr. = 97.6 torr) and 2 10 mil acetone (e-229.5 tom) what is the total vapor pressureExplanation / Answer
no of moles of non electolyte = 0.5 moles
no of moles of water = 3.2 moles
total no of moles = 0.5 + 3.2 = 3.7 moles
mole fraction of water = no of moles of water/total no of moles
= 3.2/3.7 = 0.8648
pressure of water = mole fraction of water*vapour pressure of pure water
= 0.8648*23.8 = 20.58torr
no of moles of cyclohexane = 1.7 moles
no of moles of acetone = 2.1 moles
total no moles = 1.7+2.1 = 3.8
mole fraction of cyclohexane = no of moles of cyclohexane/total no of moles
= 1.7/3.8 = 0.4473
mole fraction of acetone = 2.1/3.8 =0.5526
Total pressure = PAXA + PBXB
= 97.6*0.4473 + 229.5*0.5526
= 43.65 + 126.82 = 170.47 torr
Part C
mole fraction of cyclohexane = 0.447
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