What color did you observe after you mixed the filtrate with hexane? What else i

Question

What color did you observe after you mixed the filtrate with hexane? What else in this experiment did you observe the same color? Explain how these two reactions are related and what species must be present (is one of the products)? List all the reactant ions present in the reaction between copper (II) nitrate and sodium iodide In the first reaction copper (II) nitrate was substituted by Mg[NO_3]_2 and mixed with Nal. Did a precipitate form? In the second reaction, Nat was substituted by NaCl and mixed with copper (II) nitrate. Did a precipitate form? Determine which two ions must be present in order to form a precipitate based on the answers you gave above? What are the two spectator ions present in this reaction? Combine all he facts above Writ a molecular equation for the reaction between the copper (II) nitrate and sodium iodide Write the two half reactions (Remember this is a redox reaction) Balance each half reaction using half reaction method Write the balanced molecular equation between the copper (II) nitrate and sodium lodide

Explanation / Answer

2. Reactant ions present,

Cu2+, NO3-, Na+ and I-

3. MgI2 is highly soluble in water and thus no precipitate is formed in this case.

4. CuCl2 is highly soluble in water and thus replacing NaI with NaCl results in no precipitate formation.

5. To form a precipitate we must have Cu2+ and I- ions.

6. Spectator ions which do not participtate in precipitate formation are, NO3- and Na+

7. Combining the facts

(i) Molecular equation : Cu(NO3)2(aq) + 2NaI(aq) ----> CuI2(s) + 2NaNO3(aq)

(ii) half equations

Cu2+ + 2e- ----> Cu

2I- ----> I2 + 2e-

(iii) Same as above

(iv) Molecular equation : Cu(NO3)2(aq) + 2NaI(aq) ----> CuI2(s) + 2NaNO3(aq)

CuI2 decomposes, 2CuI2 ---> 2CuI + I2

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