Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sul

Question

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid.5.80 g of sulfuric acid and 5.80 g of lead(II) acetate are mixed.

Part A

Calculate the number of grams of sulfuric acid present in the mixture after the reaction is complete.

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Part B

Calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.

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Part C

Calculate the number of grams of lead(II) sulfate present in the mixture after the reaction is complete.

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Part D

Calculate the number of grams of acetic acid present in the mixture after the reaction is complete.

Solutions of sulfuric acid and lead(II) acetate react to form solid lead(II) sulfate and a solution of acetic acid.5.80 g of sulfuric acid and 5.80 g of lead(II) acetate are mixed.

Part A

Calculate the number of grams of sulfuric acid present in the mixture after the reaction is complete.

m =   g  

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Part B

Calculate the number of grams of lead(II) acetate present in the mixture after the reaction is complete.

m =   g  

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Part C

Calculate the number of grams of lead(II) sulfate present in the mixture after the reaction is complete.

m =   g  

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Part D

Calculate the number of grams of acetic acid present in the mixture after the reaction is complete.

Explanation / Answer

H2SO4(aq) + PbAc2(aq) = PbSO4(s) + 2HAc(aq)

m = 5.8 g of H2SO4

mol = mass/MW = 5.8/98 = 0.05918367346 mol acid

m = 5.8 g of PbAc

PbAc = masS/MW = 5.8/325.29 = 0.017830 mol of PbAc

the ratio is

1:1

for H2SO4:

final mol = initial - reacted = 0.05918367346- 0.017830 = 0.04135367346mol of H2SO4

mass = mol*MW = 0.04135367346*98 = 4.052 g of H2SO4 left

b)

there are no grams of Lead Acetetate left (all react)

c)

sinceratio is 1:1

then

0.017830 mol of PbSO4 aer formed

or

mass = mol*MW = 0.017830 *303.26 = 5.4071 g of PbSO4

d)

for Acetic acid

ratio is

1:2

so0.017830 *" = 0.03566 mol of HAc

WM of HAc = 60

then

mass = mol*MW = 0.0356660 = 2.1396g of HAc

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