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Continuing Student Scholar Application SMARTWORK 3.0 WWN9525 CHAPTER 13 HOMEWORK

ID: 943567 • Letter: C

Question

Continuing Student Scholar Application SMARTWORK 3.0 WWN9525 CHAPTER 13 HOMEWORK artwork USAJOBS Login WWN9525: Chapter 13 Ho Print Calculator Periodic Table lil Ebook Question 15 of 16 (1 point) x Incorrect X Incorrect Nitric oxide reacts rapidly with unstable nitrogen trioxide (NO3) to form NO No, (g) No NO Calculate the numeric value of the rate constant for the above reaction from the data in the table below. Initial Reaction Rates for the Formation of NO2 by the Reaction of NO with NO3at 298 K. 1 0.0014 28000 0.0014 2 0,0028 0.0014 56000 3 0.0028 0.0028 110000 The rate constant, k, is Number M. s Check Answer Q View Solution Hint 8 11 2 13 15 61 Progress: Exit Activity Activity Grade: 16 Points Possible Started: Tuesday, February 23, 2016, 10:37 AM Recorded Description: Ch. 13 Chegg.com

Explanation / Answer

The rate of reaction (-r) can be represented as

-r = K[NO]m [NO3]n     

m and n are order of reactions with respect to m and n respectively and K is the rate constant

For the first experiment

28000 = K[0.0014]m [0.0014]n         (1)

From 2nd experiment

56000= K[0.0028]m [0.0014]n         (2)

Eq.2/ Eq.1 gives

2= [0.0028/0.0014]m

2= 2m,   m=1

From experiment 3

110000= K[0.0028]m[0.0028]n      (3)

Eq.3/Eq.2 gives

(110000/56000) =[2]n

Therefore n=1

So the rate becomes –r= K[No] [NO3]

From the first experiment

28000= K[0.0014]*[0.0014]

K= 28000/(0.0014)2=1.429*1010/M.s

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