. Suppose you observe a wild population of bats with 10,000 AA individuals, 20,0
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Question
. Suppose you observe a wild population of bats with 10,000 AA individuals, 20,000 Aa individuals, and 10,000 aa individuals.
a) Is this population in Hardy-Weinberg Equilibrium? Explain your answer.
b) Suppose all aa individuals die before reproducing, while (on average) AA and Aa individuals leave the same number of offspring as each other. What are the relative fitnesses of these three genotypes?
c) Following selection, what fraction of the surviving adults would be AA? Aa? aa? What is the frequency of a following selection?
d) If these surviving adult bats mate at random, what will be the frequency of aa zygotes in the next generation?
Explanation / Answer
(a) frequency of AA =freq(aa) = 1/4, freq(Aa) =1/2.
frequency of A =freq(AA)+(1/2)freq(Aa) = 1/4 + (1/2)*(1/2) = 1/2
Under Hardy-Weinberg Equilibrium frequency of AA = p2 =1/4.
frequency of Aa = 2pq =1/2.
frequency of aa = q2 =1/4.
Yes,this population is in hardy weinberg equilibrium.
(b) fitness of aa = 0, while fitness of AA and Aa are the same.
(c) After selection, frequency of aa = 0, while the proportion of of AA and Aa is 1:2 after selection, so that frequency of AA = 1/(1+2) = 1/3 and frequency of Aa = 2/(1+2) = 2/3. Hence, frequency of a after selection = freq(aa) + (1/2)freq(Aa) = 0 + (1/2)(2/3) = 1/3.
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