Calculate the H °, S °, and G ° at 298 K for the following reaction: (Use the va

Question

Calculate the H°, S°, and G° at 298 K for the following reaction: (Use the values found in Thermodynamic Properties to calculate your answers for questions a and b.) Please see https://youtu.be/bxClXpbJyqU for assistance. Help with E,F, and G please

Al2O3(s) + 3 C(graphite) + 3 Cl2(g) 2 AlCl3(s) + 3 CO(g)

H° -66.7

S° 76.9

G° -89.0

(e) Write the expression for K.
(Format example: Kp = pHCl2 / pH2 . pCl2 would be entered as K_{p} = pHCl^{2}/pH_{2} . pCl_{2}.)

chemPad

Kp =

Your answer differs too much from the expected answer to provide useful feedback.

(f) Calculate the value of K at 298 K


(g) Estimate the value of K at 600 K.

Explanation / Answer

e)

the given reaction is

Al203 (s) + 3 C(s) + 3 Cl2 ---> 2 AlCl3 ((s) + 3 C0

solids are not considered

so

Kp = [pCO]^3 / [pCl2]^3

f)

we know that

dGo = -RTlnK

so

-89 x 1000 = -8.314 x 2998 x ln K

K = 3.99 x 10^15

so

the value of K is 3.99 x 10^15

g)

we know that

dGo = dHo - TdSo

at 600K

dGo = (-66.7 x 1000) - ( 600 x 76.9)

dGo = -112.84 x 1000

now

dGo = -RT lnK

so

-112.84 x 1000 = -8.314 x 600 x lnK

K = 6.67 x 10^9

so

the vaue of K at 600K is 6.67 x 10^9

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