Ozone Generators Some indoor air-purification systems work by converting a littl

Question

Ozone Generators Some indoor air-purification systems work by converting a little of the oxygen in the air to ozone. Which oxidizes mold and mildew spores and other biological air pollutants. The chemical equation for the ozone generation reaction is 3 O_2(g) Right arrow 2 O_3(g) It is claimed that one such system generates 4.00 g O_3 per hour from dry air passing through the purifier at a flow of 5.00 L/min. If one liter of indoor air contains 0.280 g of O_2. What mole fraction of O_2 is converted to O_3 by the air purifier? What is the percent yield of the ozone generation reaction?

Explanation / Answer

The first thing to do is to calculate the amount of oxygen that passes through the system

the flow is 0.5 L / min, since we have been provided the data about O3 in 1 hour we need to calculate the oxygen through the system in 1 hour so

0.5 L / min * 60 min = 30 L

1 liter has 0.28 g O2 so:

30 * 0.28 = 8.4 grams of Oxygen, calculate the moles of oxygen (molar mass of O2 is 32)

moles = mass / molar mass = 8.4 / 32 = 0.2625 moles so

0.2625 /

calculate the moles of O3 in 4 grams (molar mass = 48)

moles = mass / molar mass = 4 / 48 = 0.0833 moles

let make the analysis, 2 moles of O3 are produced from 3 moles of O2.

so to produce 0.0833 moles of O3 you need 0.0833 * 3 / 2 = 0.125 moles of O2.

there are 0.2625 moles of oxygen and 0.125 are transformed so:

0.125 / 0.2625 = 0.4762 mole fraction

b) theoretically you should be able to create

0.2625 * 2 / 3 = 0.175 moles of O3 , this is the theoretical yield but you only produced 0.0833 so:

percent yield = actual yield / theoretical yield

percent yield = 0.0833 / 0.175 * 100 = 47.6 %

*hope this helps =)

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.