Pre-lab Assignment: The Solution is Dilution Exploration Here are 4 solutions yo

Question

Pre-lab Assignment: The Solution is Dilution Exploration Here are 4 solutions you have prepared in your imaginary laboratory. Which of the solutions is the most concentrated? Explain your answer. The concentration of a solution is how much solute is contained in a given quantity of solution. One way to express the concentration is molarity. M. Molarity is the number of moles ol solute per liter of solution. M = mol solute/L solution Calculate the molarity of each of the solutions above. Show a sample calculation below. Then fill in the last column in the table on the next page.

Explanation / Answer

We have molar mass of Nickel(II) chloride = 129.59 g/mol

Number of moles = Mass/ Molar mass

Molarity = Number of moles/Liter of solution

Now,

Solution #1

3.00 g NiCl2 is dissolved in 100 mL water

Therefore, Number of moles = Mass/ Molar mass = 3/ 129.59 = 0.023

Molarity = Number of moles/Liter of solution = 0.023/0.1 L = 0.23 M

Solution #2

5.00 g NiCl2 is dissolved in 250 mL water

Therefore, Number of moles = Mass/ Molar mass = 5/ 129.59 = 0.038

Molarity = Number of moles/Liter of solution = 0.038/0.25 L = 0.154 M

Solution #3

10.00 g NiCl2 is dissolved in 500 mL water

Therefore, Number of moles = Mass/ Molar mass = 10/ 129.59 = 0.077

Molarity = Number of moles/Liter of solution = 0.077/0.5 L = 0.154 M

Solution #4

25.00 g NiCl2 is dissolved in 1000 mL water

Therefore, Number of moles = Mass/ Molar mass = 25/ 129.59 = 0.192

Molarity = Number of moles/Liter of solution = 0.192/1 L = 0.192 M

Solution 1 is the most concentrated

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