mistry 11-Waddell Activities and ue Dates - HAV 13 3/2/2016 11:55 PM 65.6/100 ()

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mistry 11-Waddell Activities and ue Dates - HAV 13 3/2/2016 11:55 PM 65.6/100 () 3/1/2016 03:38 PM t-Print Calculator Periodic Table Question 12 of 16 When 4.56 g of a nonelectrolyte solute is dissolved in water to make 485 mL of solution at 25 "c, the solution exerts an osmotic pressure of 955 tor What is the molar concentration of the solution? Number How many moles of solute are in the solution? Number mol What is the molar mass of the solute? Number g/mol Previous ® Give Up & View Soluson 9 Chock Arower Next Ext

Explanation / Answer

osmotic pressure = = MRT

M = (moles solute)/(L of solution); R = 0.08206 L*atm/K*mol

T=273+ 25 = 298K

p = 955 torr(1 atm)/(760 torr) = 1.2566 atm = osmotic pressure =

M = /RT = (1.2566 atm)/(0.08206 L*atm/K*mol)(298 K) =1.2566/24.45388 mol/L = 0.514mol/L

mole of solute = M x V = 0.514mol/L x 485 x10^-3L =0.024922 mol

molar mass = (g solute)/(moles solute) =4.56g x 0.024922 mol = 0.113646 g/mol

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