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Chrome Ed View History Bookmarks People Window Help File e o o Wiley PLUS c For The Reaction so3 (g) C edugen wiley plus.com Wiley PLUS Jespersen, The Molecular Nature of Matter, 7e Home Read, Study & Practice Gradebook ORION Assignment Open Assignment ASSIGNMENT Review Problem 14.072 RESOURCES At 25 °C, K 0.145 for the following reaction in the solvent CC Chapter 14 V Review Problem 2BrCE r2 4.028 their equilibrium concentrations be? If the initial concentrations of each substance in a solution are 0.0492 M, what will M R 14,032 M R 4,034 V Review Problem BrCl 14,036 the tolerance is +/-2% Prob 14.038 M R 14,040 V Review Problem 4,042 M R 14,050 M R the tolerance is +/-2% 4.051 V Review Problem 14,054 M R 4,058 M R 14.060 V Review Problem the tolerance is +/-2% 14.062 M R 14,064 Prob 14.066 License Agreement I Privacy Policy 2000-2016 John Wiley & Sons Inc. All Rights Reserved. A Division of John Wiley 8 Sons Inc. 34% Thu 9:21 PM Q. Wiley PLUS: PLUS I Help I Contact us I Log Out GENERAL CHEMISTRY- SCIENCE MAJORS (CHE 1101/1102) scREEN PRINTER VERSION BACK NEXT 4.17.3.3

Explanation / Answer

Initial     BrCl =0.0492M      Br2 =0              Cl2= 0

At equilibrium BrCl =0.0492-x   Br2=x    and Cl2= x

Where x= drop in molarityof BrCl to reach equilibrium

Kc= [Br2] [Cl2]/ [BrCl]2 =0.145

Therefore , x2/(0.0492-x)2= 0.145, taking Square root x/(0.0492-x)= 0.381

Hence x= 0.381*(0.0492-x)   ,   1.381x= 0.381*0.0492 , x =0.0136

At Equilibrium [BrCl] =0.0492-0.0136=0.0356M   [Br2]= [Cl2]= 0.0136M

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