What is the ground-state electron configuration ofa neutral atom of nickel? Expr

Question

What is the ground-state electron configuration ofa neutral atom of nickel? Express your answer in condensed form, in order of increasing orbital energy. For example, [He] 28^2 2p^2 would be entered as [He] 2s^22p^2. What is ground-state electron configuration of the sulfide ion S^2 -? Express your answer in condensed form, in order of increasing orbital energy. For example, [he]28^2 2p^2 should be entered as [He]2s^22p^2. Which element has the following configuration: [Xe]68^24f^75d^1? Enter the chemical symbol for the element

Explanation / Answer

Part A :

The atomic number of Ni is 28

The electronic configuration of Ni is [Ar] 4s^2 3d^8

Part B :

The atomic number of S is 16

The electronic configuration of S is [Ne] 3s^2 3p^4

On adding 2 electrons we get S2-

So the electronic configuration of S2- is [Ne] 3s^2 3p^6

Part C :

Given the elctronic configuration is [Xe] 6s2 4f7 5d1

The atomic number of Xe is 54 and there are 2+7+1=10 in the outer shell electrons.So totally there are 54+10 = 64 electrons so the atomic number of the element is 64.

Therefore the element with atomic number 64 is Gadolinium

Its chemical symbol is Gd

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