The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×105. Part A Ca

Question

The acid-dissociation constant for benzoic acid (C6H5COOH) is 6.3×105.

Part A Calculate the equilibrium concentration of H3O+ in the solution if the initial concentration of C6H5COOH is 6.3×102 M . Express your answer using two significant figures.

Part B Calculate the equilibrium concentration of C6H5COO in the solution if the initial concentration of C6H5COOH is 6.3×102 M .

Part C Calculate the equilibrium concentration of C6H5COOH in the solution if the initial concentration of C6H5COOH is 6.3×102 M . Express your answer using two significant figures.

Explanation / Answer

C6H5COOH + H2O <-------> C6H5COO- + H3O+
K = 6.3 x 10^-5

1) 6.3 x 10^-5 = x^2 / 6.3 x 10^-2-x
x = [H3O+] = 0.00195 M

2) = [C6H6COO-] = 0.00195 M

3) [C6H5COOH] = 6.3 x 10^-2 - 0.00202 = 0.061 M

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