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A student gets the following data for the Heat Capacity of her calorimeter. Mass

ID: 948190 • Letter: A

Question

A student gets the following data for the Heat Capacity of her calorimeter.

Mass of Calorimeter /g A1: 43.5
Mass of Calorimeter + Cold Water /g A2: 94.2
Mass of Cold Water /g (A2 – A1)
Temperature of Cold Water °C (Therm 1) measured 21.3 corrected
Temperature of Hot Water °C (Therm 2) measured 45.2 corrected
Final Temperature of Water °C (Therm 1) measured 30.0 corrected
Mass of Calorimeter + Cold Water + Hot Water/g A3: 144.7
Mass of Hot Water /g (A3-A2)

The mcalib is 0.969 and bcalib is 2.0 C for both Thermometer 1 and Thermometer 2. B
Determine the heat capacity of the calorimeter.

Explanation / Answer

Mass of Cold Water = 94.2-43.5 = 50.7grams

T1 = 21.3 c

T2 = 45.2 C

Tf = 30

mass of hot water = 144.7-94.2 = 50.5 grams

heat lost by hot water = heat gained by cold water + heatcapacity of calorimeter*DT

(50.5*4.18*(45.2-30)) = (50.7*4.18*(30-21.3))+(x*(30-21.3))

x = heatcapacity of calorimeter = 0.156 kj/C

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