if a pure R isomer has a specific rotation of -121.0 degrees and a sample contai

Question

if a pure R isomer has a specific rotation of -121.0 degrees and a sample contains 66.0% of the R isomer and 34.0% of its enantiomer, what is the observed specific rotation of the mixture HEM 2210-001-Spring16-SCHWARTZ Activities and Due Dates C16 2016 06:00 PM 732/1003/9/2016 01:32 PM PrintCalculator Periodic Table n 27 of 34 g learning lf a pure Ris er as a specific rotation of 121 and asa le contains 66 34.0% of its enantiomer, what is the observed specific rotation of the mixture? % of the R isomer and mber Number O Previous Gue Up & View Solution Check Answer O Next Exil Hint

Explanation / Answer

enantiomeric excess = (observed rotation / specific rotation)* 100

(66 - 34) = ( x / -121) *100

x = observed rotation = -38.72

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