Describe the peaks you would expect to see in the 1H and 13C nmr spectra for hyd

Question

Describe the peaks you would expect to see in the 1H and 13C nmr spectra for hydrobenzoin

this is my answer please correct me if am wrong

The peaks expected on the C NMR for hydrobenzoin

1stpeak for the carbon that is connected to the carbon attached to alcohol supposed to be the farthest from origin since it is closest to OH between 140-150 ppm

2nd peak for carbon number 2 they overlap because they have the same characteristics between 120-130ppm

3rd peak for carbons number 3 between 120-130 ppm

And 4th peak for carbons number 4 they should be the closest to 0   between 70-80 ppm

The peaks expected on the H NMR for hydrobenzoin

3 singlet that represent hydrogens on the aromatic ring around 7 ppm

                One singlet for the hydrogens that are connected to the carbon attached to OH around 4 ppm

                And one singlet for the H on the OH group cannot identify the placement because it varies

Explanation / Answer

In C NMR spectrum,we need to identify the different type of carbons.there are 5 different carbons.carbons of C2 and C3 are correct which are in the benzene ring having similar characteristics. And also there is another C in benzene ring showing a peak around 127ppm.then the carbon in the benzene ring where CH-OH is attached is more deshielded,as it is connected to benzene ring as well,shows a peak Around 140,ppm.carbon attached to OH gives a peak at 77 ppm.

In H NMR,in the benzene ring it doesn't give 3 singlets but the peak is given at 7ppm.it gives 2 triplets and a doublet where they all overlap and the other two peaks are correct. A singlet for H in OH and another singlet for H in carbon attached to OH.

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