Pb(s)| Pb2+ (1M) || Ag+ (1M) | Ag(s) Determine which of the following statements

Question

Pb(s)| Pb2+ (1M) || Ag+ (1M) | Ag(s)

Determine which of the following statements about the cell shown are True or False.

-Anions move to the silver half-cell.

-Electrons are spontaneously produced in the lead half-cell.

-As the reaction proceeds, the concentration of the silver ions increases.

-The standard cell potential, ?o, equals 1.73 V.

-The mass of the lead electrode is increasing.

-The cell, as represented by the line notation, is an electrolytic cell.

-The silver electrode is the cathode. -The lead half-cell is the cathode.

Explanation / Answer

Here the lead electrode is the anode since it has the negative cell voltage. And the silver electrode is the cathode since it has the positive cell voltage.

1) - wrong. Anions move to the lead half cell.

2)- wrong. Electrons are produced by the ozidation of the lead metal.

3)- wrong. Concentration of the silver ion decreases as silver is reduced here.

4)- wrong. E(cell)=E(cathode)-E(anode)

= 0.8-(-0.13)=0.8+0.13 = 0.93V

5)-wrong. Mass of the lead electrode decreases as lead ions are produced by oxidation.

6)- wrong. Electrolytic cell is a cell in which oxidation and reduction occur under electrical power. Here no electricity has been supplied.

7)- 1st part of the statement is correct. Silver electrode is the cathode but lead electrode is the anode

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