Consider the reaction 2H_3PO_4 rightarrow P_2O_5 + 3H_2O Using the information i

Question

Consider the reaction 2H_3PO_4 rightarrow P_2O_5 + 3H_2O Using the information in the following table, calculate the average rate of formation of P_2O_5 between 10 0 and 40 0 s Express your answer with the appropriate units. Consider the reaction 5Br^-(aq) + BrO_3^-(aq) + 6H^+ (aq) rightarrow 3Br_2 (aq) + 3H_2O(l) The average rate of consumption of Br^- is 1.46 Times 10^-4 M/s over the first two minutes. What is the average rate of formation of Br_2 during the same time interval? Express your answer with the appropriate units.

Explanation / Answer

1) 2H3PO4(aq) ------> P2O5(aq) + 3H2O(l)

average rate of formation of P2O5 = change in concentration of P2O5/Change in time

or, average rate of formation of P2O5 = (9.6*10-3)/50 = 1.92*10-4 M/s

2) 5Br-(aq) + BrO3-(aq) + 6H+(aq) ---> 3Br2(aq) + 3H2O(l)

rate of reaction = -(1/5)*rate of disappearance of Br- = (1/3)*rate of formation of Br2

Thus, rate of formation of Br2 = (3/5)*1.46*10-4 = 8.76*10-5 M/s

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