Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Use the data in the text to calculate the equilibrium constant for the following

ID: 951041 • Letter: U

Question

Use the data in the text to calculate the equilibrium constant for the following reaction:

CH3COOH(aq) +NO2- is in equilibrium with CH3COO-(aq) +HNO2 (aq)

This questions has been killing me for the last half hour. Could someone show me the solution process?

Conjugate BaseK Name of Acid Hydrofluonic acid Nitrous acid Acetysalicylik id FormulaStructure 7.1 10 45 x 10NO 1.4 × 10-s, 2.2×10 " 3.3 × 10-m H F aspirin) CHs o. 59 101 1.3 x 10 Formic acid HCOOH 1.7 10HCOO Ascorbic acid CHOHO CH,OH senzoic acid CH COOH 1.5× 10-9 1.8 x ,0- CH COOH HCN Acetic acid CH,coo 56x1010 20x 10 77 10S Phenol

Explanation / Answer

CH3COOH + NO2-   <-----------------> CH3COO- + HNO2

CH3COOH ---------------------> CH3COO- + H+

Ka = [CH3COO-][H+]/[CH3COOH]

Ka = [CH3COO-][H+]/[CH3COOH] = 1.8 x 10^-5 --------------------->1

HNO2 --------------------> NO2- + H+    , Ka

NO2 - + H+ ------------------> HNO2 , Kb

Kb = [HNO2]/[NO2-][H+]

Kb = [HNO2]/[NO2-][H+] = 2.2 x 10^-11 --------------------->2

for given reaction

CH3COOH + NO2-   <-----------------> CH3COO- + HNO2

K = [CH3COO-][HNO2]/[CH3COOH][NO2-]

if you multiply 1 and 2 you get K

K = Ka x Kb

K = 4.0 x 10^-2

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote