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To learn how to use the Nernst equation. The standard reduction potentials liste

ID: 951090 • Letter: T

Question

To learn how to use the Nernst equation. The standard reduction potentials listed in any reference table are only valid at standard-state conditions of 25 degreeC and 1 M To calculate the cell potential at non-standard-state conditions, one uses the Nernst equation. E = E^o - 2.303 RT/nF log_10 Q where E is the potential in volts, En is the standard potential in volts. R = 8.314 J/(K. mol) is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred. F = 96,500 C/(mol e) is the Faraday constant, and Q is the reaction quotient. Substituting each constant into the equation the result is E = E^o - 0.592/n log_10 Q PartE What is the cell potential for the reaction Mg(s) + Fe^2+ (aq)rightarrowMg^2+ (aq) + Fe(s) at 55 degreeC when [Fe^2+ ] = 3.80 M and [Mg^2+] = 0.210 M. Express your answer to three significant figures and include the appropriate units.

Explanation / Answer

According to nernest equation

E = E0 - 0.059/n log{[oxidised]/[reduced]}

E0cell= E0cathode - E0anode = -0.44 - (-2.37) = 1.93v

n = 2e-( no. of electrons change in redox reaction)

E = 1.93 - (0.059/2) log(0.210/3.80)

E = 1.93 -(0.059/2)*(-1.26)

E = 1.97 V

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