Choose the words that make the following statement true: \"During a televised me
ID: 951479 • Letter: C
Question
Choose the words that make the following statement true: "During a televised medical drama, a person went into cardiac arrest and stopped breathing. A doctor quickly injected sodium hydrogen carbonate straight into the heart. This would indicate that cardiac arrest leads to (Acidosis, acid poisoning, or Alkalosis, base poisoning) and that the sodium hydrogen carbonate helps to (Increase or Decrease) the pH. Explain your choices clearly." Do you expect the pH of 100.0 mL of a 0.010 M aqueous solution of sulfuric acid to be greater than 2.00, less than 2.00, equal to 2.00, cannot be determined, or none of these? Justify your choice. K_s = 1.8 Times 10^5 for HC_2H_3O_2,. At the same temperature, can aqueous solutions of HCI and HC,H30, have the same pH? Justify your choice. 21. For each of the following, is the solution acidic, basic, neutral, or cannot be determined? For each, write the equation for the dominant equilibrium which determined the pH, and justify your pH prediction. K_w = 1.0 Times 10^-14; K_a1 =6.9 Times 10^-3, K_a2, = 6.2 Times 10^-8, and K_a3= 4.8 Times 10^-13 for H_3PO_4; k_a1 = 3.0 Times 10^-2,K_a3, = 4.4 Times 10^-3, = 2.5 Times 10^-7, and = 5.6 Times 10^-10 for H_4P_2,O_7; K_a = 5.6 Times 10^4 for HNO_2; K_a = 1.8 Times 10^-5 for CH_3CO_2H; and K_b = 5.6 Times 10 ^-4forC_2H_5NH_2. 100 mL of 0.10 M Sr(ClO_4)_2 100 mL of 0.010 M CH_3 COONa 100 mL of 0.10 M C_2 H_5 NH_3^+ NO_2 50 mL of 0.10 M NaH_3 P_2 O_7 100 mL of 0.10 M Li_3 HP_2 O_7 100 mL of 0.10 M Na_4 P_2 O_7 The pH of a 0.050 M pyridine solution is 8.96 at 25 degree C. What is the K_b of pyridine? Novocain, used as a local anesthetic by dentists, is a weak base (K_b = 8.91 Times 10^-6). What is the ratio of the concentration of the base to that of its add in the blood plasma (pH = 7.40) of a patient?Explanation / Answer
18. Injection of sodium hydrogen carbonate during cardiac arrest suggests cardiac arrest leads to acidosis and that the sodium hydrogen carbonate helps to increase the pH.
19. pH of a100 ml of 0.01 M sulfuric acid would be equal to 2.
pH = -log[H+] = -log(0.01) = 2
20. No, the aqueous solution of HCl and HC2H3O2 would be lower than the pH of HC2H3O2. HCl is a string acid which dissociates completely into H+ and Cl- ions and thus pH with HCl in solution would be much lower. HC2H3O2 is a weak acid and dissociates partially and would show higher pH for the solution.
21. pH of solution,
a. 100 ml of 0.01 M Sr(ClO4)2 : pH would be neutral. It is a salt of strong acid and strong base.
H+ + OH- <==> H2O
b. 100 ml of 0.01 M CH3COONa : pH would be basic.
CH3COO- + H2O <==> CH3COOH + OH-
excess OH- in solution raises pH.
c. 100 ml of 0.1 M C2H5NH3+NO2- : pH would be acidic.
C2H5NH3+ + H2O <==> C2H5NH2 + H3O+
excess H+ in solution makes it acidic
d. 50 ml of 0.1 M NaH3P2O7 : The solution would be acidic.
H3P2O7- + H2O <==> H2P2O7^2- + H3O+
excess H+ gives the solution acidity.
e. 100 ml of 0.1 M Li3HP2O7 : The solution would be basic. Excess OH- makes the solution more basic.
HP2O7^3- + H2O <==> H2P2O7^2- + OH-
f. 100 ml of 0.1 M Na4P2O7 : The solution would be basic. Excess OH- formed makes the solution basic.
P2O7^4- + H2O <==> HP2O7^3- + OH-
22. pH = -log[H+] = 8.96
pOH = 14 - pH = 5.04
[OH-] = 9.12 x 10^-6 M
Kb = (9.12 x 10^-6)^2/0.050 = 1.66 x 10^-9
23. pH = 7.40
pOH = 14 - pH = 6.60
pOH = -log[OH-]0.028
[OH-] = 2.51 x 10^-7 M
ratio [base]/[acid] = 2.51 x 10^-7/8.91 x 10^-6 = 0.028
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