CA 0.4569 G s C Ch University of Cincinnati CX ry q C WWW sapling learning.com /

Question

CA 0.4569 G s C Ch University of Cincinnati CX ry q C WWW sapling learning.com /ibiscms/mod/ibis/view.php?id-2366009 Apps For quick access, place your bookmarks here on the bookmarks bar. Import bookmarks now. Attempts score dic Tab Print Calculator 93 Questi 2 of 7 Map 50 due to the presence of metal ions, primarily Mg2 and Ca Hardness is Hardness in groundwater is generally reported as ppm Caco3 or mmol/L Ca? To measure water hardness, a sample of groundwater is titrated with EDTA, a chelating agent, in the presence of the indicator eriochrome black T, symbolized here as In. Eriochrome black T, a weaker chelating agent than EDTA, is red in the presence of Ca2 and turns blue when Cae is removed 00 67 Ca (In) EDTA Ca EDTA +In A 50.00-mL sample of groundwater is titrated with 0.0600 M EDTA. Assume that Ca2 accounts for all of 00 the hardness in the groundwater. If 12.80 mL of EDTA is required to rate the 50.00-mL sample, what is he hardness of the groundwater in molarity and in parts per million of CaCO3 by mass? M CaCO ppm CaCO Check Answer Next Exit Give Up & V US pyright 20 2016 Sapling Le tact 7:18 PM 3/16/2016 Available From 3/9/2016 07:00 PM 3/16/2016 11:55 PM Due Date Points Possible 100 Grade Category: Default Description: Policies: Homework heck y You can view solutions when vou complete or give up on any question keep trying h q you get it right or give up You lose 5% of the points available to each answer ct att eTextbook O Help With This Topic O Web Help & Videos Technical Support and Bug Reports

Explanation / Answer

Strength of EDTA solution is 0.0600 M.

Volume of EDTA solution required for titration is 12.80 mL.

Volume of Ca2+ solution is 50.00 mL.

So, strength of the Ca2+ solution is (0.0600 M * 12.80 mL) / 50.00 mL = 0.01536 M.

Molar Mass of CaCO3 is 100 g/mol.

Mass of CaCO3 present in 1 L of solution in mg is

         (100 * 0.01536 * 1000) mg = 1536 mg

So, strength of the solution is 1536 ppm.

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.