For the following reaction, the rate law is found to be Rate = k[Ce4+][Mn2+]. 2

Q: For the following reaction, the rate law is found to be Rate = k[Ce4+][Mn2+]. 2

2Ce4+ + Tl+ ---> 2Ce3+ + Tl3+ Ce4+ + Mn2+ ===> Ce3+ + Mn3+ Ce4+ + Mn3+ ---> Ce3+ + Mn4+ Tl+ + Mn4+ ---> Tl3+ + Mn2+ Now Mn2+ is usedinitially and at end of reaction Mn2+ generated back , hence Mn2+ is catalyst , Mn3+ and Mn4+ are intermediates Hence option D

ID: 954125 • Letter: F

Question

For the following reaction, the rate law is found to be Rate = k[Ce4+][Mn2+]. 2 Ce4+ + Tl+ ---> 2 Ce3++ Tl3+ One mechanism for this reaction, containing the following elementary steps, is shown below: Ce4+ + Mn2+ ---> Ce3+ + Mn3+Ce4+ + Mn3+ Ce3+ + Mn4+Tl+ + Mn4+ ---> Tl3+ + Mn2+ Which of the following statements is true?

a)There is no catalyst and no intermediate.

b)There is no catalyst, but Mn2+ is the intermediate.

c)Mn3+ is the catalyst and Ce3+ is the intermediate

d)Mn2+ is the catalyst and Mn3+and Mn4+ are the intermediates.

e)Mn4+ is the catalyst and Mn2+ and Mn3+ are the intermediates.

f)Ce3+ is the catalyst and Tl+ and Mn4+ are the intermediates.

Explanation / Answer

2Ce4+ + Tl+ ---> 2Ce3+ + Tl3+

Ce4+ + Mn2+ ===> Ce3+ + Mn3+

Ce4+ + Mn3+ ---> Ce3+ + Mn4+

Tl+ + Mn4+ ---> Tl3+ + Mn2+

Now Mn2+ is usedinitially and at end of reaction Mn2+ generated back , hence Mn2+ is catalyst ,

Mn3+ and Mn4+ are intermediates

Hence option D

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For the following reaction, the rate law is found to be Rate = k[Ce4+][Mn2+]. 2

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