The generic reaction 2A B has the following rate laws: forward reaction: rate =

Question

The generic reaction 2A B has the following rate laws: forward reaction: rate = k_f [A]^2 reverse reaction: rate = k_r [B] where k_f is the rate constant for the forward reaction and k_r is the rate constant for the reverse reaction. At equilibrium, the two rates are equal and so k_f [A]^2 = k_r [B], The equilibrium constant for a reaction is related by the law of mass action to the rate constants for the forward and reverse reactions: K_c = [B]/[A]^2 = k_f/k_r At this temperature the rate constant for the reverse reaction is 370 M^-2 s^-1. What is k_f for the reaction? Express your answer to three significant figures and include the appropriate units. Include an asterisk to indicate multiplication in compound units, for example to write the units for a second order rate constant type M^-1 * s^-1.

Explanation / Answer

from the data

Kc = Kf/Kr

19.8 = x/370
x = Kf = 7326 M-2.s-1

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