An insulated container is used to hold 40.50 g of water at 16.80 degree C. A sam

Question

An insulated container is used to hold 40.50 g of water at 16.80 degree C. A sample of copper weighing 7.00 g is placed in a dry test tube and healed for 30 minutes in a boiling water bath at 100. 10 degree C. The heated test tube is carefully removed from the water bath with laboratory longs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 j/(g degree C). calculate the maximum temperature of the water in the insulated container after the copper metal is added.

Explanation / Answer

Heat = mCpdT

Cp for copper 0.385 J/g.oC and of water 4.184 J/g.oC

heat lost by metal = heat gained by water

let Tf be the final temperature of water

7 x 0.385 x (100.10 - Tf) = 40.50 x 4.184 x (Tf - 16.80)

269.77 - 2.695Tf = 169.452Tf - 2846.794

3116.564 = 172.147Tf

Tf = 18.10 oC

So the final temperature of water would be 18.10 oC

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.