The vapour pressure of a liquid is the pressure exerted by its vapour when the l

Question

The vapour pressure of a liquid is the pressure exerted by its vapour when the liquid and vapour states are in equilibnum. The relationship between vapour pressure p and temperature T is expressed by tho Clausius-Clapeyron equation where P_1 and P_2 are the vapour pressures at the absolute temperatures T_1 and T_2 respectively. delta_VA|, Hdegree is tho heat of vaporization of tho substance in joules per mote, and R is the (deal gas constant which is equal to 8 3145.1 K ; inol ' The heat of vaporization of water is 4.07 times 10^4 J mol^-1. The boiling point of a liquid increases as the pressure above the liquid increases In contrast to boiling food in an open pot. pressure cookers trap the steam, which raises the internal pressure, whicti raises the boiling pcxnt of water, causing a higher cooking temperature A higher cooking temperature means that the food will cook faster. The instruction booklet for your pressure cooker indicates that its highest sett ng is 110 psi You know that standard atmospheric pressure is 14 7 psi. so the booklet must mean 11.0 psi above atmospheric pressure At what temperature in degrees Celsius will your food cook in this pressure cooker set on high*? Express your answer numerically In degrees Celsius.

Explanation / Answer

As per the Clausius-Clapeyron equation:-

ln(11/14.7) = (40700/8.314)*{(1/298) - (1/T2)}

or, T2 = 292.83 K = 19.83 0C

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