I need help with 5-8 specifically URidking agents with their corresponding half-
ID: 955728 • Letter: I
Question
I need help with 5-8 specifically URidking agents with their corresponding half-reactions used in this experiment are: No,-lag, colorless) + 2 HOaq) + NOAg, red-brown) + H,01) No,-(aq, colorless) + 4 HOag) + 3 NO(L colorless) + 2 H20 Mno, (aq, purple) + 8 HOag) + 5Mn2+(aq, light pink to colorless) + 4 Hon O (e, colorless) +4 H (a) +4e 2H,OD) H,Ofaq, colorless) + 2 H+(aq) + 2e. 2 H,0 COtaq, colorless) + 2 HOaq) + 2 e- CI Grg, colorless) + H2O1) Test Tube No. Solution A Chlorine bleach and 2 drops of 6 M HC (the active ingredient in chlorine bleach is CIO) Chlorine bleach and 2 drops of 6 M HC Addition of Solution B Drops of O.1 M Fe(NH)SO Add I drop of starch solution followed by drops of 0.1 M KI Drops of O.1 M Fe(NHJ SO, (Figure 27.3) Drops of 1 M K,C,O 0.01 M KMnO, and 2 drops of 6 M H,SO 0.01 M KMnO, and 2 drops of 6 M H,SO Deionized water and 2 drops of 6 M H,SO4Drops of 0.1 M Fe(NH)(SO Deionized water and 2 drops of 6 M H,SOAdd I drop of starch solution followed by 0.1 M H,O, and 2 drops of 6 M H,SO4 0.1 M H,0, and 2 drops of 6 M H SO drops of 0.1 M KI Drops of 0.1 M Fe(NH) SO Add 1 drop of starch solution followed by drops of 0.1 MK Reducing agents with their corresponding half-reactions used in this experiment are: Culs, copper-colored) -Cu (ag, blue)+2e 3 I(ag, colorless)+I, (ag, purple) + 2 Fe2+(aq, light green to colorless) Feraq, red-brown) + e CO,' (aq, colorless) 2 COAs, colorless) + 2 e-
Explanation / Answer
5) H2SO4 + 2 H2O > SO4-2 + 2H3O+ (1)
Fe(NH4+)2(SO4)2> Fe +2 + 2 NH4+ + 2SO4-2
Fe+2 + SO4-2 > FeSO4
2 NH4+ + SO4-2 > ( NH4)2SO4
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8) H2O2 + 2 H+ + 2e- =2 H2O
2 I- = I2 + 2e-
H2O2 + 2 I- + 2 H+= I2 + 2 H2O
add the spectator ions
H2O2 + 2 KI + H2SO4 = I2 + K2SO4 + H2O
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