P_CH3OH = 0.30 - x = 0.30 - 0.00179 atm = 0.293 atm = 0.30 atm Consider the reac

Question

P_CH3OH = 0.30 - x = 0.30 - 0.00179 atm = 0.293 atm = 0.30 atm Consider the reaction N_2O(g) + NO_2(g) equivalent to 3NO(g). The value of K for this reaction at a temperature of 350 K is 2.82 times 10^-16. If 0.80 mol of N_O(g) and 0.64 mol of NO_2(G), and 0.93 mol of NO(g) are scaled in a 1 L reaction flask, what are the equilibrium molarities of N_2O(g), NO_2(g), and NO(g)? Calculate M: since all of the amounts are in a 1L flask, the calculation is simple. 0.80 mol/1 L = 0.080M. K for this reaction is very small, therefore, we can assume that x

Explanation / Answer

That value comes from 0.93/3 =0.31

because for each mol of N2O and NO2, 3 moles of NO are formed. So, when 0.93mol of NO are consumed, just 0.31mol of reagents are produced.

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