Nane a D It does not have a nos-superposable enaniomer 2 Mark chiral centers pre
ID: 959153 • Letter: N
Question
Explanation / Answer
Question 1,2 and 4, I cannot read them very well, so post those questions clearly in another question thread.
Question 3.
The only difference between I and II is that the OH is axial and in II is equatorial, so, this compounds should have to be diasteroisomers, they are in different orientation (in a ciclohexane regular conformation, this would be Trans and Cis).
Question 5.
Labeling from the first carbon that has the OH (Cause that has priority) we can see that the molecule has 4 carbons, and in position 2 we have a methyl and 3 a triple bond, so the name would be:
2-methyl-3-Butin-1-ol
As the Hydrogen is in the plane, then the direction is counterclock is S. Option B.
Hope this helps
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