A sample of hellum gas was placed in a cylinder with a sealed piston (a closed s
ID: 959409 • Letter: A
Question
A sample of hellum gas was placed in a cylinder with a sealed piston (a closed system) and the volume of the gas was measured as the pressure was slowly increased at the constant temperature. The results of this experiment are shown graphically. At what pressure does the gas occupy a volume of 5 L? What is the volume of the gas at a pressure of 5 atm? Calculate the Boyle s law constant at a volume of 2 L. Calculate the Boyle s law constant at a volume of 2 atm. The temperature of a gas is raised from 25 degree C to 50 degree C. Will the volume double It mass and pressure do not change? Why or why not? If 2.25 L of gas at 16 degree C and 1.00 atm is compressed at a pressure of 125 atm at 20 degree C. calculate the new volume of the gas. H_2O and CH_4 are gases at 150 degree C. Which exhibits more ideal behavior? Why? A gas mixture has a total pressure of 0 56 atm and consists of He and Ne. If the partial pressure of what is the partial pressure of the Ne in the mixture?Explanation / Answer
2)
T1 = 25 + 273 = 298 K
T2 = 50 + 273 = 323 K
V1 / T1 = V2 / T2
V1 / 298 =V2 / 323
V2 = 323 V1 / 298
V2 = 1.08 V1
volume will becomes 1.08 times not doubled
3)
V1 = 2.25 L , T1 = 16 + 273 = 289 K , P1 = 1.00 atm
P2 = 125 atm , T2 = 20 + 273 = 293 K
P1 V1 / T1 = P2 V2 / T2
1.00 x 2.25 / 298 = 125 x V2 / 293
V2 = new volume = 0.0177 L
4)
CH4 is more ideal
reason : in fact H2O is liquid and CH4 is gas . there are very weak vanderwaal interaction present between CH4 molecules so they still are in gasesous state . but in water there are hydrogen bonds are present they may be broken up at 150 oc but still it is polar molecule so strong interactions are present
5)
total pressure = 0.56
PHe + PNe = 0.56
0.27 + PNe = 0.56
PNe = 0.29 atm
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