(Acidic) Vo^2+ (aq) rightarrow V^3+ (aq) Ni(OH)_2 (s) rightarrow Ni_2 O_3 (s) (A

Question

(Acidic) Vo^2+ (aq) rightarrow V^3+ (aq) Ni(OH)_2 (s) rightarrow Ni_2 O_3 (s) (Acidic) No_3^- (aq) rightarrow No_2 (aq) Basic Br_2 (aq) rightarrow BrO_3^- (aq) Write the Balance not ionic equations from the following reaction in basic solution S_2 O_3^2- (aq) + I_2 (aq) rightarrow S_4 o_6^2- (aq) + I^- (aq) Mn^2+ (aq) + H_2 O_2 (aq) rightarrow MnO_2 (s) + H_2 O(I) Zn(s) + NO_3^- (aq) rightarrow NH_3 (aq) + Z_n (OH)_4^2- (aq) Bi(OH)_3 (s) + Sn (OH)_8 - (aq) rightarrow Bi(s) + Sn(OH)_6^2- (aq) Calcium level in blood can be determined by adding oxalate ions to precipitate calcium C_2 O_4 following by dividing the precipitate in aqueous acid and the resulting oxalic acid (H_2 C_2 O_4) with KmnO_4 5 H_2 C_2 O (aq) + 2 MnO_4^- (aq) + 6H^+ (aq) rightarrow 10 Co_2 () + 2 mn^2+ (aq) 8H_2 O () How many milligrams of Cn^2+ are present in 10.0 mL of blood if 2.08 ml of 0.000 988 m KmnO_4 solution needed

Explanation / Answer

1)

a ) VO+2 (aq) + 2H+ (aq) + e- --------------> V+3 (aq)+ 3H2O (l)

b) 2 Ni(OH)2 (s) + 2OH- (aq) --------------> Ni2O3 (s) + 3H2O (l)+ 2e-

c) NO3- (aq) + 2H+ (aq) + e - ----------------> NO2(aq) + H2O (l)

d) Br2 (aq) + 12OH- (aq) -------------------> 2BrO3-(aq) + 6H2O (l) + 10 e-

2)

a) 2 S2O32- + I2 --------------------> S4O62- + 2 I-

b) Mn2+ + H2O2 + 2 OH- ------------>MnO2 + 2 H2O

c) 4Zn(s) + NO3- (aq.) + 7H2O + 7OH- ----------------> NH4OH (aq.) + 4 Zn (OH)4 2- (aq)

d) 2 Bi(OH)3 + 3Sn(OH)31 + 3OH ------------------> 2Bi + 6OH- + 3Sn(OH)6-2

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