one mole of sodium chloride is added to 100ml of water in beaker A. one mole of

Question

one mole of sodium chloride is added to 100ml of water in beaker A. one mole of glucose C2H12O6 is added to 100ml of water in beaker B. how much more will the freezing point of water lowered in beaker A than in beaker B one mole of sodium chloride is added to 100ml of water in beaker A. one mole of glucose C2H12O6 is added to 100ml of water in beaker B. how much more will the freezing point of water lowered in beaker A than in beaker B one mole of sodium chloride is added to 100ml of water in beaker A. one mole of glucose C2H12O6 is added to 100ml of water in beaker B. how much more will the freezing point of water lowered in beaker A than in beaker B

Explanation / Answer

1 mol of NaCl

V = 100 ml A

1 mol of glucoose

V = 100 ml B

the only difference is that A = NaCl and has 2 ions, then i = 2

for B; i = 1

then

m = mol/kg solvent = 1/0.1 = 10

dTf = -Kf*m*i = -1.86*10*i

for A = -1.86*10*i = -1.86*10*2 = -37.2 °C

for B = -1.86*10*i = -1.86*10*1 = -18.6°C

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