Part A Calculate the activity for CS2 at x CS2 = 0.722 for a Raoult\'s law stand
ID: 963027 • Letter: P
Question
Part A
Calculate the activity for CS2 at xCS2 = 0.722 for a Raoult's law standard state using the following data: PCS2 = 446.9 Torr , and PCS2 = 512.3 Torr .
Part B
Calculate the activity coefficient for CS2 at xCS2 = 0.722 for a Raoult's law standard state using the following data: PCS2 = 446.9 Torr , and PCS2 = 512.3 Torr .
Part C
Calculate the activity for CS2 at xCS2 = 0.722 for a Henry's law standard state using the following data: PCS2 = 446.9 Torr , and kH, CS2 = 1750 Torr .
Part D
Calculate the activity coefficient for CS2 at xCS2 = 0.722 for a Henry's law standard state using the following data: PCS2 = 446.9 Torr , and kH, CS2 = 1750 Torr .
What equation would you use to even start this, and how would you go about solving for these? I didn't know there was a difference between 'activity' and 'activity coefficient'...
Explanation / Answer
Part A
Calculation for CS2 at XCS2 = 0.722 at Raoult's law standard state
We have ; PCS2 = 446.9 Torr and P?CS2 = 512.3 Torr
Formula,
Activity (a) = PCS2/P*CS2
Activity (a) = 446.9/512.3 = 0.8723
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Part B
Calculation for activity coefficient (?) for CS2 at XCS2 = 0.722 at Raoult's law standard state.
Given, PCS2 = 446.9 Torr and P?CS2 = 512.3 Torr.
Formula and calculations,
Activity (a) = PCS2/P*CS2 = 446.9/512.3 = 0.8723
Activity coefficient (?) =Activity x concentration = 0.8723 x 0.722 = 0.6298.
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Part C
Calculation for the activity for CS2 at XCS2 = 0.722 at Henry's law standard state.
Given, PCS2 = 446.9 Torr and K (CS2) = 1750 Torr .
Activity (a) = PCS2/KCS2 = 446.9 / 1750 = 0.2554
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Part D
Calculation for the activity coefficient for CS2 at XCS2 = 0.722 at Henry's law standard state
Given, PCS2 = 446.9 Torr and KCS2 = 1750 Torr.
Activity(a) = PCS2/KCS2 = 446.9 / 1750 = 0.2554
Activity coefficient (?) = Activity / KCS2 = 0.2553 / 1750 = 1.46 x 10-4.
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