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Part A Calculate the activity for CS2 at x CS2 = 0.722 for a Raoult\'s law stand

ID: 963027 • Letter: P

Question

Part A

Calculate the activity for CS2 at xCS2 = 0.722 for a Raoult's law standard state using the following data: PCS2 = 446.9 Torr , and PCS2 = 512.3 Torr .

Part B

Calculate the activity coefficient for CS2 at xCS2 = 0.722 for a Raoult's law standard state using the following data: PCS2 = 446.9 Torr , and PCS2 = 512.3 Torr .

Part C

Calculate the activity for CS2 at xCS2 = 0.722 for a Henry's law standard state using the following data: PCS2 = 446.9 Torr , and kH, CS2 = 1750 Torr .

Part D

Calculate the activity coefficient for CS2 at xCS2 = 0.722 for a Henry's law standard state using the following data: PCS2 = 446.9 Torr , and kH, CS2 = 1750 Torr .

What equation would you use to even start this, and how would you go about solving for these? I didn't know there was a difference between 'activity' and 'activity coefficient'...

Explanation / Answer

Part A

Calculation for CS2 at XCS2 = 0.722 at Raoult's law standard state

We have ; PCS2 = 446.9 Torr and P?CS2 = 512.3 Torr

Formula,

Activity (a) = PCS2/P*CS2

Activity (a) = 446.9/512.3 = 0.8723

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Part B

Calculation for activity coefficient (?) for CS2 at XCS2 = 0.722 at Raoult's law standard state.

Given, PCS2 = 446.9 Torr and P?CS2 = 512.3 Torr.

Formula and calculations,

Activity (a) = PCS2/P*CS2 = 446.9/512.3 = 0.8723

Activity coefficient (?) =Activity x concentration = 0.8723 x 0.722 = 0.6298.

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Part C

Calculation for the activity for CS2 at XCS2 = 0.722 at Henry's law standard state.

Given, PCS2 = 446.9 Torr and K (CS2) = 1750 Torr .

Activity (a) = PCS2/KCS2 = 446.9 / 1750 = 0.2554

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Part D

Calculation for the activity coefficient for CS2 at XCS2 = 0.722 at Henry's law standard state

Given, PCS2 = 446.9 Torr and KCS2 = 1750 Torr.

Activity(a) = PCS2/KCS2 = 446.9 / 1750 = 0.2554

Activity coefficient (?) = Activity / KCS2 = 0.2553 / 1750 = 1.46 x 10-4.

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