x, Take Test: Pre Lab 11:Cai X In the calorimetry II lab, the reaction mixture w

Question

x, Take Test: Pre Lab 11:Cai X In the calorimetry II lab, the reaction mixture will consist of 2.00 mL 0.550 M HCag), 2.00 mL distilled water and 1.00 mL 1.00 M NaOH. Based on the Do not enter the units in the answer box data (same table will be completed in lab), calculate the items below, each to three significant figures. (2 pts each) qiroaction) + C(water) x mass (solution) × Tesolution) + 2.62 J.oc-aT(water)-0 and AH(reaction, per H20 formed)- gfreaction/mols OH-greactionyNaOHx LNaoH) Item Run 1 ·00 mL NaOH NaOH oles NaOH calorimeter stir bar stir bar + solution initialHCn °c final. T(solution.°C 45 °c 184 Jig °c) Warnings appear when half the time, 5 minutes, 1 minute, and 30 seconds reman. Multiple This test allows muitiple attempts. Attempts Force Once started, this test must be completed in one sitting. Do not leave the test before clicking Save and Submit

Explanation / Answer

1. Volume of HCl = 2.00 mL = 2.00 x 10-3 L

Molarity of HCl = 0.550 M

Moles of HCl = Molarity x Volume

                       = 0.550 M x 2.00 x 10-3 L

                       = 1.10 x 10-3 moles

2. Molarity of NaOH = 1.0 M

Volume of NaOH = 1.00 mL = 1.00 x 10-3 L

Moles NaOH = Molarity x Volume

                       = 1 M x 1.00 x 10-3 L

                       = 1.00 x 10-3 moles

3. Mass of calorimeter + stir bar = 4.617 g

Mass of calorimeter + stir bar + solution = 9.696 g

So, Mass of solution = Mass of calorimeter + stir bar + solution - Mass of calorimeter + stir bar

                                  = 9.696 g - 4.617 g

                                  = 5.079 g

                                  = 5.08 g

4. Initial temperature = 20.07 oC

Initial temperature = 22.45 oC

T (solution) oC = 22.45 oC - 20.07 oC = 2.38 oC

Related Questions

Navigate

• Browse (All)
• Browse X
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.