Show work or include as much as explanation as needed to support the calculation

Question

Show work or include as much as explanation as needed to support the calculation. If you write just the find answer; you will not get out credit. Round of the answer to Apply Hess's law to calculate the delta H for the target reaction ; 5 c (s) + CH_2 (g) right arrow C_2 H_2 (f) use the following there reactions and their corresponding delta H values: C_2 H_12 (f) + SO_2 (g) right arrow SCO_2 (g) + CH_2 O (f) delta H = - 35005.8 Kj C (s) + O_2 (g) right arrow CO (g) delta H = -303.5 KJ 2H_2 (g) + O_2 (g) right arrow 2H_2 O (g) delta H = -483.5 KJ

Explanation / Answer

Multiply (2) by 5, since we need 5 C

multiply (3) by 3, since we need 6 H2

invert (1) since we need glucose in the left

so

Overall effect:

H1 =+ 3505.8 kJ (positive since it was inverted)

H2 = -393.5*5 = -1967.5 kJ

H3 = -483.5*3 = -1450.5kJ

then

Hrxn total = H1+H2+H3 = 3505.8 -1967.5 -1450.5 = 87.8 kJ

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