A student performed this experiment, using a cocktail peanut. Before it was burn
ID: 964379 • Letter: A
Question
A student performed this experiment, using a cocktail peanut. Before it was burned, the peanut half weighed 0.353 g. After burning, the residue weighed 0.016 g. The energy released by the combustion increased the temperature of 200.0 ml of water in the calorimeter by 7.2° C.
1.) calculate the mass of peanut consumed in the combustion.
2.) Calculate the mass, in kilograms, of water heated.
3.) Calculate the total energy released by the combustion, using the water temperature increase, the water mass, and the specific heat capacity of water.
4.) Calculate the energy released per gram of peanut consumed in the combustion.
Explanation / Answer
A student performed this experiment, using a cocktail peanut. Before it was burned, the peanut half weighed 0.353 g. After burning, the residue weighed 0.016 g. The energy released by the combustion increased the temperature of 200.0 ml of water in the calorimeter by 7.2° C.
1.) calculate the mass of peanut consumed in the combustion.
the mass of peanut consumed in the combustion =
0.353 g- 0.016 g
=0.337 g
2.) Calculate the mass, in kilograms, of water heated.
Density of water = 1.00g/ ml
Density = mass / volume
Mass = density *volume
=200.0 ml*1.00g/ml
=200 g
1.00 kg=1000 g
200 g*1.00kg/1000 g= 0.200 kg
3.) Calculate the total energy released by the combustion, using the water temperature increase, the water mass, and the specific heat capacity of water.
Q= mcdT
Q = 200 g*4.184 J/ g° C *7.2° C
Q= 6024.96 J 6.02 kJ
4.) Calculate the energy released per gram of peanut consumed in the combustion.
To calculate the energy released per gram of peanut consumed in the combustion divide total energy by the grams of peanut:
6024.96 J/0.337 g=17878.22 J/g
=17.87 kJ/g
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