. An acid-base equilibrium system is created by dissolving 0.50 mol CH3CO2H in w

Question

. An acid-base equilibrium system is created by dissolving 0.50 mol CH3CO2H in water to a volume of 1.0 L. What is the effect of adding 0.50 mol CH3CO2–(aq) to this solution?

1. The pH of the solution will equal 7.00 because equal concentrations of a weak acid and its conjugate base are present.

2. Some CH3CO2H(aq) will ionize, increasing the concentration of CH3CO2–(aq) and increasing the pH.

3.Some CH3CO2–(aq) will react with H3O+, increasing the concentration of CH3CO2H(aq) and reestablishing the solution equilibrium.

A. 1 only b. 2 only c. 3 only d. 1 & 3 E 1,2,3

Explanation / Answer

An acid-base equilibrium system is created by dissolving 0.50 mol CH3CO2H in water to a volume of 1.0 L. What is the effect of adding 0.50 mol CH3CO2-(aq) to this solution?

Here, some CH3COO- will react with the H3O+, which will increase the concentration of CH3COOH and reestablish the equilibrium

Answer: c) 3 only

Related Questions

Navigate

• Browse (All)
• Browse #
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.