x V-Girls On Top x V Hyun Jin M 17.5 L of M container A holds 757 mL California
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x V-Girls On Top x V Hyun Jin M 17.5 L of M container A holds 757 mL California State University, Li www.saplinglearning.com/ibiscms/mod/.bis/view.php?id=2542003&proceed-1; Thanks for using C Food in Thailand-T -scholar M The secret to Sams a Amazon.com: Doubl 2 at 25 degree + x 16.3 L N2 At 25°C And 1 2 x x :: Apps a Amazon.com: Doubl a Amazon.com: Doubl a Amazon.com: Allegr Other Bookmarks Sapling Learning Jump to... # Logout @ Help Sapling Learning California State University, Northridge-CHEM 101 -Spring16-NGUYEN-GRAFF Activities and Due Dates -Quiz 16 (Partial pressure and KMT) My Assignment Resources 4/9/2016 11:55 PM A o/10 Assignment Information Available From 3/26/2016 06:00 PM Due Date: Points Possible: Grade Category: Graded Description: Policies: Attempts Score Time Remaining: 39 M145 Gradebook Calculator Periodic Table Question 1 of 7 4/9/2016 11:55 PM Map 10 sapling learning Container A holds 797 mL of ideal gas at 2.30 atm. Container B holds 124 mL of ideal gas at 4.70 atm. If the gases are allowed to mix together, what is the partial pressure of each gas in the total volume? 4 45 min quiz update You can check your answers. You can view solutions after the due date You only have one attempt per question. Number Gas A atm Number Help With This Topic Gas B atm Web Help & Videos Technical Support and Bug Reports Previous O Check Answer Next Exit Hint Copyright © 2011-2016 Sapling Learning, Inc.·114 about uscareersptprivacy policy terms of usecontact us helpExplanation / Answer
Ptotal = (PA VA + PB VB) / (VA + VB)
Ptotal = ( 2.3 x 797 + 4.7 x 124 ) / (797 + 124)
Ptotal = 2.62 atm
For A: P1V1 = P2V2 or (2.30 atm)(0.797 L) = (P2)(0.92 L) and P2 for gas in A = 1.99 atm
For B: P1V1 = P2V2 or (4.7 atm)(0.124 L) = (P2)(0.92 L) and P2 for gas in A = 0.633 atm
Partial Pressure of gas in A = 1.99 / 2.62 = 0.7595 atm
Partial Pressure of gas in B = 0.633/2.62 = 0.2416 atm
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