Will rate! Check all that apply according to the chart. B: ? = 91.1 nm C: If lig

Question

Will rate! Check all that apply according to the chart.

B: ? = 91.1 nm

C: If light with a wavelength shorter than 91.1 nm is used to excite the H atom, the excess energy will become the kinetic energy of the ejected electron.

How the results of parts (b) and (c) related to the plot shown below? 0 Frequency oose all that apply. The wavelength calculated in part (b) is analogous to Vmax on the plot. The frequency associated with the wavelength calculated in part (b) is analogous to Vmay on the plot. The wavelength calculated in part (b) is analogous to vo on the plot. The frequency associated with the wavelength calculated in part (b) is analogous to vo on the plot. Any excess kinetic energy imparted to the ejected electron corresponds to the straight line to the left of Vo Any excess kinetic energy imparted to the ejected electron corresponds to the sloped line to the right of vo Any excess kinetic energy imparted to the ejected electron corresponds to the space above tho line. Any excess kinetic energy imparted to the ejected electron corresponds to the space under tho line. max

Explanation / Answer

Solution:

* The frequency associated with wavelength calculated in part (B) is analogous to Neu Max on the plot.

* An excess kinetic energy imparted to the ejected electron,corrosponds to space above the line

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