1. What is the balanced chemical equation for the reaction used to calculate fH

Question

1. What is the balanced chemical equation for the reaction used to calculate fH of CaCO3(s)?

2. For a given reaction, the heat capacity (CP) of the reactants is 50.0 J/mol K and for the products is 65.0 J/mol K. If the enthalpy of reaction is 150.0 kJ/mol at 300K, what is the best estimate of rxnH at 320K? Give your answer to 4 significant digits.

3. The reaction in the previous question is carried out adiabatically starting at 300 K. What is the final temperature after the reaction goes to completion? rxnH300 = -150.0 kJ/mol CP(reactants) = 50 J/molK CP(products) = 65 J/molK

Tf =   K

Explanation / Answer

1. the balanced chemical equation for the reaction used to calculate fH of CaCO3(s) is as:

Ca(s) + C(s) + 3/2 O2(g) --> CaCO3(s).

2. rxnH = m x c x (T)

Suppose the mass of the CaCO3 in above reaction to be 1 gram

T = T2-T1 = (320-300) = 20 k

C of reaction = (65 -50) = 15 J/mol K

rxnH = 1 x 15 x 20 = - 300 kJ/mol

3. rxnH = m x c x T

T = rxnH / (m x c)

T = -150 / 15 = 15 K

T = 300 + 15 = 315 K

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