Overall reaction The reactions for the ionization energy of sodium and the elect

Question

Overall reaction The reactions for the ionization energy of sodium and the electron affinity of chlorine can be combined to give the reaction shown in the introduction: Na(g)Cl(g)+eNa(g)+Cl(g)Na+(g)+eCl(g)Na+(g)+Cl(g) Part C The ionization energy for sodium is 496 kJ/mol. The electron affinity for chlorine is -349 kJ/mol. Use these values and Hess's law to calculate the change in enthalpy for the following reaction per mole of reagent: Na(g)+Cl(g)Na+(g)+Cl(g), H=? Express your answer with the appropriate units. H per mole =

Explanation / Answer

Given:

The ionization energy of sodium

Na (g) ---> Na+ (g) +e H = +496 kJ/mol ....(1)

The electron affinity of chlorine

Cl (g) + e- ---> Cl- (g) H = - 349 kJ/mol ....(2)

We need enthalpy of reaction

Na(g)+Cl(g) --> Na+(g)+ Cl-(g) .....(3)

equaiton 3 = Equation (1) + equation (2)

H3 = H1 +H2

H = 496 - 349 = +147 KJ mole

So enthalpy of reaction per mole will be +147KJ

Related Questions

Navigate

• Browse (All)
• Browse O
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.