1)The boiling point of benzene C6H6 is 80.10°C at 1 atmosphere. A nonvolatile, n

Question

1)The boiling point of benzene C6H6 is 80.10°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in benzene is TNT (trinitrotoluene). How many grams of TNT, C7H5N3O6 (227.1 g/mol), must be dissolved in 245.0 grams of benzene to raise the boiling point by 0.450 °C ?

2)The boiling point of water H2O is 100.00°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is antifreeze (ethylene glycol).

If 13.02 grams of antifreeze, CH2OHCH2OH (62.10 g/mol), are dissolved in 296.3 grams of water.

The molality of the solution is

The boiling point of the solution is

Explanation / Answer

1) DTf = i*kb*m

0.45 = 1*2.65*(x/227.1)*(1000/245)

x= mass of TNT added = 9.45 grams

2)

molality of solution = (13.02/62.1)*(1000/296.3) = 0.71 molal

DTb = i*Kb*m

(x-100) = 1*0.512*0.71

boiling point of solution = 100.363 C

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