Double displacement reactions: Answer the following questions: Complete the form
ID: 968285 • Letter: D
Question
Double displacement reactions: Answer the following questions:
Complete the formula equation and write the word equations for the reactions given below. formulas AND NAMES MUST BE CORRECT. (Remember is displacement reactions, it can help to write H_2O as HOH) Label each equation as DR (double displacement) or SR (single displacement). The following observations were obtained from individual experiments with HCl: From the list below, choose the reactants that added to HCl would result in the observation.Explanation / Answer
MgO(s) + 2HCl(aq) ---------> MgCl2(aq) + H2O(l)
Magnesium oxide + hydrochloric acid --à Magnesium chloride
Double displacement reaction
Mg + 2HCl ---------------> H2 + MgCl2
Magnesium oxide + hydrochloric acid Magnesium chloride
Single displacement reaction
H2SO4 + Zn(OH)2 ---------------à ZnSO4 + 2 H2O
Sulfuric acid + Zinc hydroxide Zinc sulphate
Double displacement reaction
Sn + 2HCl ------> SnCl2 + H2
Tin + hydrochloric acid Tin(II)chloride
Single displacement reaction
Cu(OH)2 + H2SO4 ---à 2 H2O + CuSO4
Copper(II) hydroxide + Sulfuric acid Copper (II) sulphate
Double displacement reaction
2Na + 2HCl ==> 2NaCl + H2 (g) Test tube felt warm and bubbles of gas
NaOH + HCl --à NaCl + H2O no chnages
Na2CO3 + 2HCl === 2NaCl + H2O + CO2(g) bubbles of gas
CuO(s) + 2 HCl(aq) CuCl2(aq) + H2O(l) no changes
AgNo3(aq) + HCl(aq) = AgCl(s) + HNo3(aq) solid will form
NaNO3 + HCl--> HNO3 + NaCl no changes
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