A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter cont

Question

A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10^2 H2O. If the formula weight of this nutrient substance is 114 g/mol, what is the fuel value (in nutrient Cal) if the temperature of the water increased 5.70 degrees celsius?
Calculate the fuel value in kilojoules (kJ) A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10^2 H2O. If the formula weight of this nutrient substance is 114 g/mol, what is the fuel value (in nutrient Cal) if the temperature of the water increased 5.70 degrees celsius?
Calculate the fuel value in kilojoules (kJ) A 0.0500 mol sample of a nutrient substance is burned in a bomb calorimeter containing 2.00 x 10^2 H2O. If the formula weight of this nutrient substance is 114 g/mol, what is the fuel value (in nutrient Cal) if the temperature of the water increased 5.70 degrees celsius?
Calculate the fuel value in kilojoules (kJ)

Explanation / Answer

Mass of water= 200gms ( water masss is assumed to be gram)

Temperature rise = 5.7 deg.c, specific heat of water= 4.18 g/deg.c

Heat taken by water= 200*4.18*5.7=4765.2 Joules =4.7652 Kj

This much heat is removed by water when 0.05 moles of substance is burned

mass of substance= 0.05*114=5.7 gms

Fuel value = 4.7652 Kj or 4.7652/0.05 Kj/mol=95.304 Kj/mole.

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